Glucose (molar mass=180.16 g/mol) is a simple, soluble sugar.Glucose solutions are used to treat patients with low bloodsugar.Suppose you prepare a glucose solution using the describedprocedure.Step 1: Dissolve 257.6 g of glucose in enough water to make500.0 mL of solution.Step 2: Transfer 19.4 mL of the solution to a new flask and addenough water to make 250.0 mL of dilute solution.What is the concentration (in M) of the glucose solution at theend of the procedure?
Glucose (molar mass=180.16 g/mol) is a simple, soluble sugar. Glucose solutions are used to treat patients with low blood sugar. Suppose you prepare a glucose solution using the described procedure. Step 1: Dissolve 257.6 g of glucose in enough water to make 500.0 mL of solution. Step 2: Transfer 19.4 mL of the solution to a new flask and add enough water to make 250.0 mL of dilute solution. What is the concentration (in M) of the glucose solution at the end of the procedure?
Chemistry 101
The density at $20^{\circ} \mathrm{C}$ of a 0.258 $\mathrm{m}$ solution of glucose in water is
1.0173 $\mathrm{g} / \mathrm{mL}$ , and the molar mass of glucose is 180.2 $\mathrm{g} / \mathrm{mol}$ . What is the molarity of the
solution?
Hello, everyone. Thanks for joining me. This Hallstrom, as we go through some calculations looking at glucose levels for a diabetic before and after the diabetic ingests glucose. For this problem, a diabetic patient has a concentration of one 40 0.1 40 grams of glucose, huh? 100 mill leaders of blood. The impatient ingests 40 grams of glucose and their blood glucose level rises to 0.240 grams of glucose per 100 milliliters of blood. Our body has her body, has five leaders of blood and were asked to solve for the following before and after. So we'll do br before calculations first, but we're supposed to find were asked to find moles of glucose per milliliters of blood again before and after. And total malls of glucose in the body and total mass of glucose. So those are the things we're going to solve for? We're going to 123 calculations for this, and then we'll do the same three calculations for this. Let's begin first. The first calculation will be looking for moles of glucose. And I'm just gonna indicate that Fergie right now per mil, leader of B for blood okay, were given for our initial. These are our before calculations were given 0.140 grams of glucose per 100 milliliters of blood. So to set this calculation up, it's pretty simple. We're just going to you the molar mass of 1 80.16 grams of glucose per mole of glucose. So one point point 140 times we could skip the one divided by 1 80.16 divided by 100 do their mouth on this one. And the answer is 7.77 times 10 to the minus six moles. Uh, mill leader. Oh, blood and I better put bowls of glucose right here. That's our first question. The next question that we were asked was, um, Total How many? How many moles of glucose total. And this one is also going to be pretty simple because we can use this value 7.77 times, 10 to the minus six moles of glucose per mil leader, and we're gonna get rid of milliliters. We're gonna multiply that by five leaders in her body, and this will give us how many moles total. So if we do the math for this problem. We end up with 3.89 times 10 to the minus two malls of glucose 3.89 times 10 to the minus two Moles of glucose. That's answer number to answer one answer to and easy peasy For the last one, we're going to convert our bulls of glucose 3.89 times 10 to the minus two Moles of glucose. We're gonna multiply that by the molar mass of glucose 1 80.16 grams per mole for a final answer of 7.1 grams. Answer three 7.77 times 10 to the six Moles of glucose 3.89 times tend to the SEC minus second molds of glucose total in our five liters of blood and 7.1 grams of glucose and her five liters of blood for the next calculation thes air. After calculations, we're gonna do the exact same thing. Except this time we're using 0.240 grams of glucose per 100 milliliters of blood. So again we're gonna have calculation one, two and three. And let's start with calculation 10.240 grams of glucose and 100 milliliters, and we're looking for an answer that is in balls per mil a leader. In order to do that, we're going to change our grams. Two malls of glucose do our math on this problem, and the answer will be 1.33 times 10 to the minus fifth moles per mil Leader. That's answer Number one two wants is to note wants to find total malls. So we're gonna take our answer from this answer 1.33 times 10 to the minus 50 bulls per milliliter. And we're going to convert this. The letters cross out and we have five liters of blood in our bodies. So the answer for this problem for the total moles on her body is 6.66 times 10 to the minus two molds of glucose in her entire body. And last but not least, we're going to simply convert this answer back to grams 6.66 times 10 to the minus second moles of glucose multiply that by 1 80.16 grams per mole, and her final answer is 12.0 grams of glucose. There didn't take us too long to do six separate calculations. Thanks for joining
Hello. Today we'll be doing problem. 45 questions asked. What is the more mass of insulin? So we know that one ATM Equals 760 mercury. Mhm. And if we do a conversion factor, you would know that if you divide this number you will get. Uh huh. You're 100 three two 9 80. M. And they are there will be the osmotic pressure of the solution. So if you know the formula for asthma pressure. But yeah. Yeah, You went on this one is the octomom pressure morality of the solution. The gas law constant. And this one temperature. So what you need to do is rearrange your formula. So how did it cause osmotic pressure divided by gas constant times temperature. I'm gonna make this one, correct. Here we go. So plug your numbers in 0.00329 ATM divided by zero point 08- one. Yeah. In times too. I eight K. Yeah. Now did you have the malaria solution? Yeah. Yeah. You need to substitute this number for the volume solution and solve the most of solid. So capital and equals 1.35 times 10. Mhm. For times 0.125 l equals 1.69 times 10. Okay. Mhm. Well, so the number of moles of solute is defined as follows. And he calls mass. Bye bye. More mass. So substitute this one. Mhm. Yeah. Mhm. Yeah. Yeah. Mm. And this should begin 5.92 times and two power 3 g or vote more. So that's the answer to number five. Sorry, # 45. Okay. That's if it has been.
Mhm So the cup contains 100 g of glucose And we know from the molar mass that one mole of glucose is going to be 180 .18g. And the cup contains 350 ml, so we'll divide out the volume and we'll convert that to leaders. There's 1000 mL in one leader. Then we see milliliters cans out with milliliters, grants, cancels out with grams and we're left with most per liter or the polarity, which is what we want. And when we do the math out, We get 100 Divided by 180.18 divided by 3 50 they were multiplied by 1000 Comes out to 1.59 Mueller.
In this question, we're working with a glucose solution. Um it has a volume of 10 ml. The solution has a mass of 10.483 g. And then when the solution is being evaporated until dry, it leaves solid of 0.5-4 g. In the a part of the question. I need to calculate the mass mass percentage in this case. So the mass mass percentage will just be The mass of the solid, which is 3.5-4g, divided by the mass of the solution, Which is 10 483 g. And then I need to multiply this with 100 in order to get percentage. This gives me a value of 5.00 1%. So this is the mass mass percentage of blue coast. In this case, number B, we have to calculate the molar concentration of the glucose. Now remember that molar concentration is we're going to calculate this in terms of moles the elitists, there's a number of moles of glucose for one liter solution per one liter solution. So let's start off with the mass of the solid 0.5 to four g there the volume of the solution that I'm working with here. Now remember I said murder concentration. We usually work in terms of moles per liter. So I'm going to convert the volume, which is in terms of milliliters here, two L. Now, 10 ml is the same as 0.010 leaders. So I'm working with um 7.5 to 4 g of glucose um of which the formula is C six H 12 oh six. And This is the 0.010 L of solution. All right, let's see. What do I have to multiply this with in order to determine the molar concentration, which will be a number of moles of glucose For one L of solution. Yeah, so I have to get rid of the grams here and I have to bring in a number of moles. So this will be the inverse Of Molar mass that I need to multiply with. The molar mass of glucose is 180.18 g of C six, age 12 06, which is the glucose for one mole of glucose. So here I am working with the inverse of the molar mass of the glucose so that I can get rid of the grams here and I end up with 0.291. Um moles are not grams Because this is what I want malls of glucose C6 h 12 06 for one liter of solution. And I know that is The molar concentration then 0.291 mola Um of C6 age 12 06, which is the glucose. Right? So to recap, I needed to calculate the mass mass percentage of um This glucose which is in solution 1st. So for this purpose um I used the mass of the solid divided by the mass of the solution And then multiplied by 100 in part B of the question. Had to calculate the Molar concentration. For this purpose. I converted the volume which is given in milliliters to lead his first so that I can end with a unit that's in terms of leaders moles per liter, which is then the molar concentration. Right? So I had the mass of the solid divided by the volume of the solution, times the molar mass in order to get rid of the grams unit. And then I ended up with the number of moles of glucose, the leader of solution, which is in my molar concentration.